Question

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For the first situation,

Profit % $=C.P.S.P.−C.P. ×100=5$

$=>S.P.−C.P.=0.05C.P.$

$=>S.P.=1.05C.P$ --- (1)

For the second situation, Selling price $=$ Selling price of 1st situation $−Rs63$

And Cost price is $30$ % less or $=70$ % of C.P. $=0.7C.P.$

So, Profit % $=C.P.S.P.−C.P. ×100=30$

$=>0.7C.P.(S.P.−63)−0.7C.P. ×100=30$

$=>S.P.−63−0.7C.P.=0.21C.P.$

$=>S.P.=0.91C.P+63$ --- (2)

From, equations 1, 2

$1.05C.P.=0.91C.P+63$

$=>0.14C.P.=63$

$C.P.=Rs450$

Thus, cost price of the bicycle $=Rs450$

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