I am trying to make an option price calculator.
Can anyone please guide me on what is N for the calculations for Nifty and how to calculate that.
Thank you.
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The options price for a Call, computed as per the following Black Scholes formula:
C = S * N (d1) - X * e- rt * N (d2)
and the price for a Put is : P = X * e- rt * N (-d2) - S * N (-d1)
where :
d1 = [ln (S / X) + (r + σ2 / 2) * t] / σ * sqrt(t)
d2 = [ln (S / X) + (r - σ2 / 2) * t] / σ * sqrt(t)
= d1 - σ * sqrt(t)
C = price of a call option
P = price of a put option
S = price of the underlying asset
X = Strike price of the option
r = rate of interest
t = time to expiration
σ = volatility of the underlying
N represents a standard normal distribution with mean = 0 and standard deviation = 1
ln represents the natural logarithm of a number. Natural logarithms are based on the constant e (2.71828182845904).
Can anyone please guide me on what is N for the calculations for Nifty and how to calculate that.
Thank you.
//----------------------------------------------------------------
The options price for a Call, computed as per the following Black Scholes formula:
C = S * N (d1) - X * e- rt * N (d2)
and the price for a Put is : P = X * e- rt * N (-d2) - S * N (-d1)
where :
d1 = [ln (S / X) + (r + σ2 / 2) * t] / σ * sqrt(t)
d2 = [ln (S / X) + (r - σ2 / 2) * t] / σ * sqrt(t)
= d1 - σ * sqrt(t)
C = price of a call option
P = price of a put option
S = price of the underlying asset
X = Strike price of the option
r = rate of interest
t = time to expiration
σ = volatility of the underlying
N represents a standard normal distribution with mean = 0 and standard deviation = 1
ln represents the natural logarithm of a number. Natural logarithms are based on the constant e (2.71828182845904).